Simplification - Class 5 - Mathematics
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Exercise 15 - Simplification | R.S. Aggarwal | Mathematics | Class 5
$12+9 \div 3$
To solve the given expression (12 + 9 \div 3), we first follow the order of operations:
Division: (9 \div 3 = 3)
Addition: (12 + 3 = 15)
Thus, (12 + 9 \div 3 = 15).
$16 \times 8 \div 4$
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Sign up now$23-8 \times 2$
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Sign up now$32 \div 8+4 \times 6-2$
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Sign up now$100-72 \div 8+4 \times 3$
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Sign up now$30+75 \div 15 \times 4-18$
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Sign up now$8 \times 6+24 \div 6-18$
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Sign up now$56-36 \div 4 \times 2+7$
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Sign up now$56 \div 14 \times 3-10 \div 5+1$
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Sign up now$198-42 \times 15 \div 5+6$
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Sign up now$105 \times 14 \div 7+6-1$
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Sign up now$17+34 \div 17 \times 5-20$
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Sign up nowExercise 16 - Simplification | R.S. Aggarwal | Mathematics | Class 5
$20-\{18 \div(7-2+1)\}$
The result of the expression $$20-{18 \div(7-2+1)}$$ is $\boxed{17}$.
$23-[6+\{8-(9-6)\}]$
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Sign up now$2[19-\{7+(12 \div 4)\}]$
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Sign up now$40-[12+\{16-(12 \div 3)\}]$
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Sign up now$[\{(30-\overline{9-6}) \div 3\} \times 6+6]$
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Sign up now$12-[6 \div 3+\{8 \div 2(8-6)\}]$
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Sign up now$[40 \div\{19-3(6-\overline{4-1})\}]$
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Sign up now$[105 \div\{23+2(9-\overline{5-2})\}]$
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Sign up nowQuestions Bag 1 - Simplification | R.S. Aggarwal | Mathematics | Class 5
Which of the following operations is performed first in simplifying a numerical expression?
(a) +
(b) -
(c) $x$
(d) $\div$
When simplifying a numerical expression, operations are carried out according to the order of operations, which is often remembered by the acronym PEMDAS:
P: Parentheses first
E: Exponents (ie: powers and square roots, etc.)
MD: Multiplication and Division (from left to right)
AS: Addition and Subtraction (from left to right)
Given the options:
(a) + (b) - (c) $x$ (Multiplication) (d) $\div$ (Division)
The operations performed first, according to PEMDAS, are Multiplication and Division, from left to right. So, both (c) Multiplication and (d) Division are performed before addition and subtraction, and between them, the one that comes first from left to right in the expression is done first. Thus, both (c) and (d) can be considered the correct answer as they are performed concurrently based on their appearance from left to right in the expression.
$8 \times 8-8=$
(a) 0
(b) 1
(c) 56
(d) 64
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Sign up nowQuestion Bag 2 - Simplification | R.S. Aggarwal | Mathematics | Class 5
Fill in the blanks.
(a) $5-6+3=$
(b) $3 \times 8 \div 4=$
(c) $6+6-6 \div 6 \times 6=$
(d) $4+4+4+4 \div 4=$
(e) $100+50 \times 2=$
(g) $15 \times 5-60 \div 15=$
(f) $80+800 \div 8=$
(h) $16+8 \div 4-2 \times 3=$
(i) $21 \div 7+16-5 \times 3=$
(j) $5 \times 50+57-57 \div 57=$
Here are the solutions for each part:
(a) $5-6+3=2$
(b) $3 \times 8 \div 4=6$
(c) $6+6-6 \div 6 \times 6=6$
(d) $4+4+4+4 \div 4=13$
(e) $100+50 \times 2=200$
(f) $80+800 \div 8=180$
(g) $15 \times 5-60 \div 15=71$
(h) $16+8 \div 4-2 \times 3=12$
(i) $21 \div 7+16-5 \times 3=4$
(j) $5 \times 50+57-57 \div 57=306$
Simplify:
(a) $289+153 \div 17-8 \times 19$
(b) $7614+832 \times 48 \div 16-8$
(c) $7823-128 \div 16$ of $4-3973$
(d) $80+[20 \times\{20-(10 \div 5)\}]$
(e) $[\{64-(12+13)\} \div 3]+15$
(f) $10 \times 10+[400 \div\{100-(50-\overline{3 \times 10})\}]$
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