# Relations and Functions - Class 11 - Mathematics

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## Extra Questions - Relations and Functions | NCERT | Mathematics | Class 11

If $A = \{2, 4, 6, 8\}$ and $B = \{1, 2, 3, 4, 5\}$, then $A - B =$

A $\{1,3,5\}$

B $\{\}$

C $\{6, 8\}$

D $\{2,4\}$

The correct answer is **Option C**: $\{6, 8\}$.

To find the set difference $A - B$, we remove all elements of set $B$ from set $A$:

Given: $$ A = {2, 4, 6, 8} $$ $$ B = {1, 2, 3, 4, 5} $$

The elements of $A$ that are not in $B$ are $6$ and $8$. Thus: $$ A - B = {6, 8} $$

If $f(x) + f(x+a) + f(x+2a) + \ldots + f(x+na) = \text{constant}$; $\forall x \in$ R and a $> 0$ and $f(x)$ is periodic, then the period of $f(x)$ is

A $(n+1)a$

B $e^{(n+1)a}$

C $na$

D $e^{n a}$

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