Question

Which of the following reactions will give H₃BO₃ (boric acid)?

  • Option 1) B₂O₃ + H₂O →
  • Option 2) BCl₃ + H₂O →
  • Option 3) Na₂B₄O₇ + H₂O + HCl →
  • Option 4) B₂H₆ + H₂O →

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Answer

Among the given options, all four reactions are capable of producing boric acid ($ \text{H}_3\text{BO}_3 $).

Option 1: Reaction of Boron Trioxide with Water

$$ \text{B}_2\text{O}_3 + 3\text{H}_2\text{O} \rightarrow 2\text{H}_3\text{BO}_3 $$

Option 2: Reaction of Boron Trichloride with Water

$$ \text{BCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{H}_3\text{BO}_3 + 3\text{HCl} $$

Option 3: Reaction of Sodium Tetraborate with Water and Hydrochloric Acid

$$ \text{Na}_2\text{B}_4\text{O}_7 + 7\text{H}_2\text{O} + 2\text{HCl} \rightarrow 4\text{H}_3\text{BO}_3 + 2\text{NaCl} $$

Option 4: Reaction of Diborane with Water

$$ \text{B}_2\text{H}_6 + 6\text{H}_2\text{O} \rightarrow 2\text{H}_3\text{BO}_3 + 6\text{H}_2 $$

Thus, all four reactions yield boric acid ($ \text{H}_3\text{BO}_3 $):

  • A: Yes
  • B: Yes
  • C: Yes
  • D: Yes

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