When propyne is treated with aqueous $H_{2}SO_{4}$ in the presence of $HgSO_{4}$, the major product is: A Propanal B Propyl hydrogen sulphate C Acetone D Propanol

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The correct option is C Acetone.

Similar to alkanes and alkenes, alkynes are also immiscible in water and typically do not react with it under standard conditions. Nevertheless, an alkyne can undergo a reaction with water when subjected to warming with $\mathrm{HgSO}_{4}$ and dilute $\mathrm{H}_{2}SO_{4}$ at $333 \mathrm{K}$. This reaction results in the formation of a carbonyl compound.

In the specific case of propyne, the addition of one molecule of water under these conditions leads to the formation of acetone. This process involves tautomerism, where the initial addition product (enol form) rearranges to the more stable keto form, which in this case is acetone.

Therefore, the correct answer is option C, Acetone.

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