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The volume of 50 g of a substance is 20 cm^3. If the density of water is 1 g cm^-3, will the substance float or sink?

Question

The volume of 50 g50 \mathrm{~g} of a substance is 20 cm320 \mathrm{~cm}^{3}. If the density of water is 1 g cm31 \mathrm{~g} \mathrm{~cm}^{-3}, will the substance float or sink?

Answer

To determine if the substance will float or sink in water, we need to compare its density with that of water.

The density (ρ\rho) of a substance can be calculated using the formula:

ρ=massvolume \rho = \frac{\text{mass}}{\text{volume}}

Given the mass and volume of the substance, we can calculate its density:

ρsubstance=50 g20 cm3=2.5 g/cm3\rho_{\text{substance}} = \frac{50 \text{ g}}{20 \text{ cm}^3} = 2.5 \text{ g/cm}^3

Since the density of water is 1 g/cm31 \text{ g/cm}^3, and the density of the substance is 2.5 g/cm32.5 \text{ g/cm}^3, the substance is denser than water.

Therefore, the substance will sink in water.

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