Question

The total weight of $10^{22}$ molecular units of $\mathrm{CuSO}{4} \cdot 5 \mathrm{H}{2} \mathrm{O}$ is nearly 41.45 g.

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Answer


The correct option is A.

To determine the weight of (10^{22}) molecular units of (\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}):

$$ 6.023 \times 10^{23} , \text{molecular units} \rightarrow 240.6 , \text{g} $$

Given:

$$ 10^{22} , \text{molecular units} \rightarrow x , \text{g} $$

We use the proportion:

$$ x = \frac{240.6 \times 10^{22}}{6.023 \times 10^{23}} $$

Upon calculation, we find:

$$ x = 4.144 , \text{g} $$


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