Question

The products obtained when chlorine gas reacts with cold and dilute aqueous NaOH are:

  • (A) ClO2^- and ClO3^-
  • B Cl^- and ClO^-
  • C Cl^- and ClO2^-
  • (D) ClO^- and ClO3^-

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Answer


The correct answer is (B) $\mathrm{Cl}^{-}$ and $\mathrm{ClO}^{-}$.

When chlorine gas ($\mathrm{Cl_2}$) reacts with cold and dilute aqueous sodium hydroxide ($\mathrm{NaOH}$), the resulting products are sodium chloride ($\mathrm{NaCl}$), sodium hypochlorite ($\mathrm{NaOCl}$), and water ($\mathrm{H_2O}$). The reaction can be expressed as follows:

$$ \mathrm{Cl}{2} + 2 \mathrm{NaOH} , (\text{cold and dilute}) \rightarrow \mathrm{NaCl} + \mathrm{NaOCl} + \mathrm{H}{2}\mathrm{O} $$

For reference, when chlorine gas reacts with hot and concentrated sodium hydroxide, the reaction produces sodium chloride, sodium chlorate ($\mathrm{NaClO_3}$), and water. The equation is:

$$ 3 \mathrm{Cl}{2} + 6 \mathrm{NaOH} , (\text{hot and concentrated}) \rightarrow 5 \mathrm{NaCl} + \mathrm{NaClO}{3} + 3 \mathrm{H}_{2}\mathrm{O} $$


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