Question

The magnifying power of compound microscope is 32. If the magnifying power of the objective is 8, then the magnifying power of the eyepiece is:

A) 24 B) 256 C) 4 D) 40

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Answer

To find the magnifying power of the eyepiece, we can use the relationship between the total magnification and the magnifications provided by the objective and the eyepiece.

The formula for the total magnifying power ($ m $) of a compound microscope is given by:

$$ m = m_{o} \times m_{e} $$

Where:

  • $ m_o $ is the magnifying power of the objective.
  • $ m_e $ is the magnifying power of the eyepiece.

Given:

  • The total magnifying power, $ m = 32 $
  • The magnifying power of the objective, $ m_o = 8 $

We need to find $ m_e $:

$$ 32 = 8 \times m_{e} $$

Solving for $ m_e $:

$$ m_{e} = \frac{32}{8} = 4 $$

So, the magnifying power of the eyepiece is 4.

Final Answer: C


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