# The magnifying power of compound microscope is 32. If the magnifying power of the objective is 8, then the magnifying power of the eyepiece is: A) 24 B) 256 C) 4 D) 40

## Question

The magnifying power of compound microscope is 32. If the magnifying power of the objective is 8, then the magnifying power of the eyepiece is:

A) 24 B) 256 C) 4 D) 40

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## Answer

To find the magnifying power of the eyepiece, we can use the relationship between the total magnification and the magnifications provided by the objective and the eyepiece.

The **formula** for the total magnifying power ($ m $) of a compound microscope is given by:

$$ m = m_{o} \times m_{e} $$

Where:

- $ m_o $ is the magnifying power of the objective.
- $ m_e $ is the magnifying power of the eyepiece.

Given:

- The total magnifying power, $ m = 32 $
- The magnifying power of the objective, $ m_o = 8 $

We need to find $ m_e $:

$$ 32 = 8 \times m_{e} $$

Solving for $ m_e $:

$$ m_{e} = \frac{32}{8} = 4 $$

So, the magnifying power of the eyepiece is **4**.

**Final Answer:** C

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