Question

The correct order of dipole moment is:

(A) $\mathrm{CH}{4} < \mathrm{NF}{3} < \mathrm{NH}{3} < \mathrm{H}{2}\mathrm{O}$

(B) $\mathrm{NF}{3} < \mathrm{CH}{4} < \mathrm{NH}{3} < \mathrm{H}{2}\mathrm{O}$

(C) $\mathrm{NH}{3} < \mathrm{NF}{3} < \mathrm{CH}{4} < \mathrm{H}{2}\mathrm{O}$

(D) $\mathrm{H}{2}\mathrm{O} < \mathrm{NH}{3} < \mathrm{NF}{3} < \mathrm{CH}{4}$

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Answer

:

The correct option is (A): $$ \mathrm{CH}{4} < \mathrm{NF}{3} < \mathrm{NH}{3} < \mathrm{H}{2}\mathrm{O} $$

Here, the dipole moments of the molecules are as follows:

  • Methane ($\mathrm{CH}_{4}$): 0 D
  • Nitrogen trifluoride ($\mathrm{NF}_{3}$): 0.2 D
  • Ammonia ($\mathrm{NH}_{3}$): 1.47 D
  • Water ($\mathrm{H}_{2}\mathrm{O}$): 1.85 D

Given these values, the order of increasing dipole moment is: $$ \mathrm{CH}{4} < \mathrm{NF}{3} < \mathrm{NH}{3} < \mathrm{H}{2}\mathrm{O} $$


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