Stomach acid is a solution of HCl with a concentration of 1.2 x 10^3 M. What is the pH of stomach acid? A 3.92 B 2.92 C 4.92 D 1.92
Question
Stomach acid is a solution of $HCl$ with a concentration of $1.2 \times 10^{3}$ M. What is the pH of stomach acid?
A 3.92
B 2.92
C 4.92
D 1.92
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Answer
:
Given:
The concentration of stomach acid (a solution of $ \mathrm{HCl} $) is $1.2 \times 10^{3}$ M.
Stepbystep calculation:

Ionization of $\mathrm{HCl}$:
$\mathrm{HCl}$ is a strong acid and is $\mathbf{100%}$ ionized in solution, which implies: $$ [\mathrm{H_3O}^+] = 1.2 \times 10^{3} , \text{M} $$

Calculating the $\mathbf{pH}$:
The formula to find $\mathbf{pH}$ is: $$ \mathrm{pH} = \log [\mathrm{H_3O}^+] $$
Substituting the concentration into the formula: $$ \mathrm{pH} = \log (1.2 \times 10^{3}) $$

Evaluating the logarithm:
Using the properties of logarithms: $$ \mathrm{pH} = 2.92 $$
Hence, the $\mathbf{pH}$ of the stomach acid is $\textbf{2.92}$.
Correct Option:
$\mathbf{B}$ $$ 2.92 $$
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