Question

Stomach acid is a solution of $HCl$ with a concentration of $1.2 \times 10^{-3}$ M. What is the pH of stomach acid?

A 3.92
B 2.92
C 4.92
D 1.92

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Answer

:

Given:

The concentration of stomach acid (a solution of $ \mathrm{HCl} $) is $1.2 \times 10^{-3}$ M.

Step-by-step calculation:

  1. Ionization of $\mathrm{HCl}$:

    $\mathrm{HCl}$ is a strong acid and is $\mathbf{100%}$ ionized in solution, which implies: $$ [\mathrm{H_3O}^+] = 1.2 \times 10^{-3} , \text{M} $$

  2. Calculating the $\mathbf{pH}$:

    The formula to find $\mathbf{pH}$ is: $$ \mathrm{pH} = -\log [\mathrm{H_3O}^+] $$

    Substituting the concentration into the formula: $$ \mathrm{pH} = -\log (1.2 \times 10^{-3}) $$

  3. Evaluating the logarithm:

    Using the properties of logarithms: $$ \mathrm{pH} = 2.92 $$

Hence, the $\mathbf{pH}$ of the stomach acid is $\textbf{2.92}$.

Correct Option:

$\mathbf{B}$ $$ 2.92 $$


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