Question

Reductive ozonolysis of a terpenoid of the following structure gives how many different products:

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Answer

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In the given terpenoid structure, identify the positions where ozonolysis will cleave the molecule. Reductive ozonolysis typically cleaves the double bonds to form aldehydes and ketones.

  1. First Double Bond: The double bond within the six-membered ring will be cleaved, resulting in the formation of two products.
  2. Second Double Bond: The double bond outside the ring, near the methyl groups, will also be cleaved, resulting in the formation of one additional product.

Thus, three different products are formed as a result of the reductive ozonolysis of the given terpenoid.

Final Answer: 3


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