Question

If the probability of a quadrilateral being a square is 0.4, then the probability of the quadrilateral not being a square is 0.6.

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Answer

:

The correct option is $\mathbf{C}$ (0.6).

Let $P(S)$ represent the probability of a quadrilateral being a square.

Let $P(S')$ represent the probability of a quadrilateral not being a square.

Since $P(S)$ and $P(S')$ are complementary events, their probabilities add up to 1: $$ P(S) + P(S') = 1 $$

Given: $$ P(S) = 0.4 $$

Substitute this value into the equation: $$ 0.4 + P(S') = 1 $$

Solve for $P(S')$: $$ P(S') = 1 - 0.4 $$ $$ P(S') = 0.6 $$

Thus, the probability of a quadrilateral not being a square is $0.6$.


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