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If H is the harmonic mean between p and q, then the value of (H/p) + (H/q) is: (A) 2 (B) (pq) / (p + q) (C) (p + q) / (pq) (D) None of these

Question

If HH is the harmonic mean between pp and qq, then the value of Hp+Hq\frac{H}{p} + \frac{H}{q} is:

(A) 2 (B) pqp+q\frac{pq}{p+q} (C) p+qpq\frac{p+q}{pq} (D) None of these

Answer

Let's first identify the harmonic mean HH between pp and qq. The formula for the harmonic mean is given by:

H=2pqp+q H = \frac{2pq}{p + q}

To find the value of Hp+Hq\frac{H}{p} + \frac{H}{q}, we will substitute the expression for HH into the equation:

Hp+Hq=2pqp+qp+2pqp+qq \frac{H}{p} + \frac{H}{q} = \frac{\frac{2pq}{p+q}}{p} + \frac{\frac{2pq}{p+q}}{q}

Simplify each term individually:

2pqp+qp=2pqp(p+q)=2qp+q \frac{\frac{2pq}{p+q}}{p} = \frac{2pq}{p(p+q)} = \frac{2q}{p+q}

2pqp+qq=2pqq(p+q)=2pp+q \frac{\frac{2pq}{p+q}}{q} = \frac{2pq}{q(p+q)} = \frac{2p}{p+q}

Now, combine the simplified terms:

Hp+Hq=2qp+q+2pp+q \frac{H}{p} + \frac{H}{q} = \frac{2q}{p+q} + \frac{2p}{p+q}

Since the denominators are the same, we can add the numerators:

2q+2pp+q=2(q+p)p+q \frac{2q + 2p}{p+q} = \frac{2(q + p)}{p+q}

When we simplify this fraction, the p+qp+q terms cancel out:

2(p+q)p+q=2 \frac{2(p + q)}{p+q} = 2

Therefore, the value of Hp+Hq\frac{H}{p} + \frac{H}{q} is 2.

Correct answer: (A) 2

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