Question

How many of the following compounds are planar and nonpolar:

  • $ \mathrm{C}{3}\mathrm{O}{2} $
  • $ \mathrm{CH}{2}=\mathrm{C}=\mathrm{CH}{2} $
  • $ \mathrm{BF}_{3} $
  • $ \mathrm{CCl}_{4} $
  • $ \mathrm{SF}_{6} $
  • $ \mathrm{XeF}_{4} $
  • $ \mathrm{IF}_{4}^{-} $
  • $ \mathrm{IF}_{7} $
  • $ \mathrm{SF}_{4} $
  • $ \mathrm{ClF}_{3} $

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Answer

For the given compounds, we need to determine those that are both planar and nonpolar. Let's analyze each compound accordingly:

  1. $ \mathrm{C}{3}\mathrm{O}{2} $:

    • Planar: Yes
    • Nonpolar: No
  2. $ \mathrm{CH}{2}=\mathrm{C}=\mathrm{CH}{2} $:

    • Planar: No (It is an allene with even number of pi bonds, making the structure non-planar as the bonds are perpendicular to each other.)
    • Nonpolar: No
  3. $ \mathrm{BF}_{3} $:

    • Planar: Yes
    • Nonpolar: Yes
  4. $ \mathrm{CCl}_{4} $:

    • Planar: No
    • Nonpolar: Yes
  5. $ \mathrm{SF}_{6} $:

    • Planar: No
    • Nonpolar: Yes
  6. $ \mathrm{XeF}_{4} $:

    • Planar: Yes
    • Nonpolar: Yes
  7. $ \mathrm{IF}_{4}^{-} $:

    • Planar: Yes
    • Nonpolar: Yes
  8. $ \mathrm{IF}_{7} $:

    • Planar: No
    • Nonpolar: Yes
  9. $ \mathrm{SF}_{4} $:

    • Planar: No
    • Nonpolar: No
  10. $ \mathrm{ClF}_{3} $:

    • Planar: No
    • Nonpolar: No

Based on this analysis, the compounds that are both planar and nonpolar are:

  • $ \mathrm{BF}_{3} $
  • $ \mathrm{XeF}_{4} $
  • $ \mathrm{IF}_{4}^{-} $

Thus, there are 3 compounds that fit the criteria of being planar and nonpolar.


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