Question

Cl$_2$ reacts with water and forms

A) HCl + HOCl
B) HCl + O$_2$ + O$_3$
C) HCl + HOCl + O$_3$
D) HOCl + O$_2$

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Answer

When chlorine gas ($Cl_2$) reacts with water ($H_2O$) at room temperature, a disproportionation reaction occurs. This reaction involves the transformation of chlorine into two different compounds where it is both oxidized and reduced.

The chemical equation for this reaction is: $$ Cl_2 (g) + H_2O (l) \rightarrow HCl (aq) + HOCl (aq) $$

Here, Hydrochloric acid (HCl) and Hypochlorous acid (HOCl) are formed as the products.

  • HCl is Hydrochloric acid, which is a strong acid in aqueous solution.
  • HOCl is Hypochlorous acid, which is a relatively weak acid but a strong oxidizing agent.

This reaction makes the aqueous solution slightly acidic due to the presence of hydrochloric acid.

Therefore, the correct answer is A) HCl + HOCl.

These compounds make the chlorine water solution useful for applications like bleaching paper because of the strong oxidizing properties of hypochlorous acid.


Final Answer: A) HCl + HOCl


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