Question

(a) Two insulated charged copper spheres A and B have their centres separated by a distance of $50 \mathrm{~cm}$. What is the mutual force of electrostatic repulsion if the charge on each is $6.5 \times 10^{-7} \mathrm{C}$ ? The radii of $\mathrm{A}$ and $\mathrm{B}$ are negligible compared to the distance of separation.

(b) What is the force of repulsion if each sphere is charged double the above amount, and the distance between them is halved?

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Answer

Part (a)

With the given values, the electrostatic force of repulsion between the spheres is: [ F = 0.01521 , \text{N} ]

Part (b)

When the charges are doubled and the distance is halved, the electrostatic force of repulsion is: [ F' = 0.24336 , \text{N} ]

So the results are:

  • (a) 0.01521 N

  • (b) 0.24336 N


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