# A particle moves rectilinearly, following a parabolic s-t graph. The average velocity of the particle over a time interval from t=0.5 s to t=1.5 s can be determined from the given graph: Please note that the missing values 'restilinearly' and 'parabolic s-t grap' have been corrected to 'rectilinearly' and 'parabolic s-t graph', respectively.

## Question

A particle moves rectilinearly, following a parabolic s-t graph. The average velocity of the particle over a time interval from $t=0.5$ s to $t=1.5$ s can be determined from the given graph:

Please note that the missing values 'restilinearly' and 'parabolic s-t grap' have been corrected to 'rectilinearly' and 'parabolic s-t graph', respectively.

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## Answer

The correct answer is: **0**

Since the $s$-t graph is **parabolic** and symmetrical about $t = 1 \ \text{s}$, we find that the displacements at $t = \frac{1}{2} \ \text{s}$ and $t = \frac{3}{2} \ \text{s}$ are equal. This means that the line segment AB, which joins these two coordinates, is **parallel to the $t$-axis**. Thus, the slope of AB is zero. Consequently, the **average velocity** during the time interval $\Delta t = 1 \ \text{s}$ is indeed **zero**.

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