Question

Here is the translation of the given text into English:


9 moles of 'D' and 14 moles of ' $E$ ' react in a closed vessel according to the given reactions. If there are 4 moles of ' $G$ ' present in the vessel, how many moles of ' $B$ ' will be obtained at the end of the reaction? (The % yield of the reaction is specified along with the reaction)

$$ \begin{array}{l} \text{Step 1: } 3D + 4E \xrightarrow{80\%} = 5C + A \\ \text{Step 2: } 3C + 5G \xrightarrow{50\%} = 6B + F \end{array} $$


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Answer


To determine the number of moles of ( B ) produced at the end of the reaction, we need to follow the given chemical reactions and their efficiencies.

Step 1: Reaction 1

$$ 3 D + 4 E \xrightarrow{80%} 5 C + A $$ Given:

  • 9 moles of ( D )
  • 14 moles of ( E )

To find the moles of ( C ) produced:

  1. From the stoichiometry of the reaction, 3 moles of ( D ) react with 4 moles of ( E ).
  2. With 80% efficiency, the moles of ( C ) produced from 9 moles of ( D ) can be calculated as: $$ \text{Moles of } C = \frac{5}{3} \times 9 \times 0.8 = 12 \text{ moles} $$

Step 2: Reaction 2

$$ 3 C + 5 G \xrightarrow{50%} 6 B + F $$ Given:

  • 12 moles of ( C ) (from Reaction 1)
  • 4 moles of ( G )

To find the moles of ( B ) produced:

  1. From the stoichiometry of the reaction, 3 moles of ( C ) react with 5 moles of ( G ).
  2. With 50% efficiency, we can calculate the moles of ( B ) produced from 4 moles of ( G ) as: $$ \text{Moles of } B = \frac{6}{5} \times 4 \times 0.5 = 2.4 \text{ moles} $$

Thus, the correct answer is: Final Answer: A


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